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From theory to practice. Filling in the numbers.

Obtaining some figures from [Taylor et al] and [Hutchison 1976]...

Here are some estimates relevant parameters.

The surface area of the lake A is approximately tex2html_wrap_inline3373 and the volume tex2html_wrap_inline3197 is approximately tex2html_wrap_inline3377, therefore the L is about 1m. Huizenga's report says a head difference of about 0.3m is needed to compensate for evaporation rate at tex2html_wrap_inline3379. The head difference is I/k where tex2html_wrap_inline3381 thus we can estimate tex2html_wrap_inline3383.

How transient are transients? The time constant for the transients is typically -k/A thus the half-life is :-
equation1414
Which implies...
equation1420
Thus tex2html_wrap_inline3189 is 36 days.

When the flow is in steady state from sea to lake with tex2html_wrap_inline3387, the time taken for the concentration to double tex2html_wrap_inline3389, (assuming no fresh water inflow) is...
equation1444
Solving for tex2html_wrap_inline3389...
equation1446
Assuming the lake is initially at sea water salinity (tex2html_wrap_inline3343), then the concentration doubling time is tex2html_wrap_inline3395 days.

When the flow is steady state from lake to sea with tex2html_wrap_inline3381. The half-life for the salt concentration tex2html_wrap_inline3399 is...
equation1459
Thus tex2html_wrap_inline3401 days.

How much water is needed to make up the head loss of 0.3m? tex2html_wrap_inline3403. Given that the Full Supply Capacity of the anticipated new dams is tex2html_wrap_inline3405 it is unlikely that any compensation release of water would flush the system.


John Carter
Tue Jun 17 09:50:07 SAT 1997